document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=274696>Question 274696</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the function that models the area (A) of an equillateral triange in terms of the length (X) of one of its sides:\r<BR>\n" );
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document.write( "Where am I going wrong...please help!\r<BR>\n" );
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document.write( "I've began solving as follows:\r<BR>\n" );
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document.write( "Length - X<BR>\n" );
document.write( "height - h\r<BR>\n" );
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document.write( "Area of a triangle is = 1/2 (length times height) <BR>\n" );
document.write( "Because this is an equilateral triange, the Length (X) is equal to its Height (H<BR>\n" );
document.write( "Therefore,\r<BR>\n" );
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document.write( "A= 1/2 (X times X)<BR>\n" );
document.write( "A= 1/2 x squared\r<BR>\n" );
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document.write( "so, the function is: A(X)=1/2x squared.\r<BR>\n" );
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document.write( "I know this is the wrong answer because my textbook gives the final answer but does a horrible job of explaining the solution. Please help! Thanks! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #200460 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=200460\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> \"Because this is an equilateral triange, the Length (X) is equal to its Height (H\"<BR>\n" );
document.write( "___ this is NOT true\r<BR>\n" );
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document.write( "an altitude (height) of an equilateral triangle divides the triangle into two 30º-60º-90º triangles<BR>\n" );
document.write( "___ with the length corresponding to the hypotenuse\r<BR>\n" );
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document.write( "the ratio of height to length is ___ sqrt(3) / 2\r<BR>\n" );
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document.write( "so ___ A = (1/2) (X) (X (sqrt(3)) / 2) = X^2 (sqrt(3)) / 4 </SPAN>\n" );
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