document.write( "Question 274662: I have tried watching the video as well as look at the actual problems in the book, but neither actually go over a problem just like the 1 that they have on the quiz. I am taking an on line basic college algebra class in TX. The instructor is non-available and I have asked several others to help with no assistance. I can not go any further in the homework/weekly quizzes until I get this question answers. I do not want the answer I would like help with the process please. The basic question will look like this negative 3 is less thank or equal to 3 minus 2x over 3 (fraction form) is less than or equal to 3.\r
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\n" ); document.write( "\n" ); document.write( "Miss ALS\r
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Algebra.Com's Answer #200417 by JBarnum(2146)\"\" \"About 
You can put this solution on YOUR website!
The basic question will look like this negative 3 is less thank or equal to 3 minus 2x over 3 (fraction form) is less than or equal to 3.\r
\n" ); document.write( "\n" ); document.write( "\"-3%3C=%28%283-2x%29%2F3%29%3C=3\" i hope i got the question written correctly from you.
\n" ); document.write( "u solve for x with the 2 seperate equations and remember dividing by a negative chages directions of the inequality signs.
\n" ); document.write( "\"-3%3C=%28%283-2x%29%2F3%29%3C=3\"
\n" ); document.write( "\"-3%3C=%28%283-2x%29%2F3%29\" and \"%28%283-2x%29%2F3%29%3C=3\"
\n" ); document.write( "________________________________________
\n" ); document.write( "\"-3%3C=%28%283-2x%29%2F3%29\" first equation
\n" ); document.write( "\"-3%283%29%3C=%28%283-2x%29%2F3%29%283%29\"multiply by 3
\n" ); document.write( "\"-9%3C=%28%283-2x%29%2Fcross%283%29%29cross%283%29\"cross cancel
\n" ); document.write( "\"-9-3%3C=%283-2x%29-3\"subtract 3
\n" ); document.write( "\"-12%2F-2%3C=-2x%2F-2\"divide by -2, remember what i said above
\n" ); document.write( "\"6%3E=x\"
\n" ); document.write( "_________________
\n" ); document.write( "\"%28%283-2x%29%2F3%29%3C=3\"second equation
\n" ); document.write( "\"%28%283-2x%29%2F3%29%283%29%3C=3%283%29\"multiply by 3
\n" ); document.write( "\"%28%283-2x%29%2Fcross%283%29%29cross%283%29%3C=9\"cross cancel
\n" ); document.write( "\"3-2x-3%3C=9-3\"subtract 3
\n" ); document.write( "\"-2x%2F-2%3C=6%2F-2\"divide by -2, remember what i said above
\n" ); document.write( "\"x%3E=-3\"
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\n" ); document.write( "the inequality will look like:
\n" ); document.write( "\"-3%3C=x%3C=6\" so x= (-3,6)\r
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