document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=274615>Question 274615</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of a number and twice a second number is 12. If the difference between 3 times the first number and the second number is 1, find the numbers.\r<BR>\n" );
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document.write( "Thank You </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #200403 by </B><A HREF=/tutors/aboutme.mpl?userid=JBarnum><B>JBarnum(2146)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JBarnum><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JBarnum><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=200403\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a= one number<BR>\n" );
document.write( "b= second number<BR>\n" );
document.write( "a+2b=12, a=12-2b<BR>\n" );
document.write( "3a-b=1<BR>\n" );
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document.write( "a+2b=12<BR>\n" );
document.write( "6a-2b=2<BR>\n" );
document.write( "7a=14<BR>\n" );
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document.write( "a=12-2b<BR>\n" );
document.write( "2=12-2b<BR>\n" );
document.write( "-10=-2b<BR>\n" );
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