document.write( "Question 274526: in the past no shows were 20% of the people registered in a race. there are 225 registered this year. what is the probability of a. 220 no-shows?
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Algebra.Com's Answer #200394 by stanbon(75887)\"\" \"About 
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in the past no shows were 20% of the people registered in a race.
\n" ); document.write( "there are 225 registered this year.
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\n" ); document.write( "Binomial problem with n = 225 ; p = 0.2
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\n" ); document.write( "what is the probability of
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\n" ); document.write( "a. 220 no-shows?
\n" ); document.write( "P(x = 220) = 225C220(0.2)^220(0.8)^5 = binompdf(225,0.2,220)
\n" ); document.write( "My calculator says the answer is zero to 8 decimal places.
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\n" ); document.write( "B. 50 or less no-shows?
\n" ); document.write( "P(0<= x <=50) = binomcdf(225,0.2,50) = 0.8211
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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