document.write( "Question 274561: Your villiage depends for its food on a nearby fish pond. One day the wind blows a water lilly seed int the pond and it begins to grow. It doubles its size every day, its growth is such that it will cover the entire pond (and smother the fish population)in 45 days. You are away on vacation and the villagers depend on your vigilance and intelligence to handle their affairs. Without you present they will take action only on regular work days and only when the lilly covers half the pond or more. The lilly will cover half the pond ____ days after it first starts growing. The day it reaches that size happens to be a holiday...
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Algebra.Com's Answer #200377 by CharlesG2(834)\"\" \"About 
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Your villiage depends for its food on a nearby fish pond. One day the wind blows a water lilly seed int the pond and it begins to grow. It doubles its size every day, its growth is such that it will cover the entire pond (and smother the fish population)in 45 days. You are away on vacation and the villagers depend on your vigilance and intelligence to handle their affairs. Without you present they will take action only on regular work days and only when the lilly covers half the pond or more. The lilly will cover half the pond ____ days after it first starts growing. The day it reaches that size happens to be a holiday...\r
\n" ); document.write( "\n" ); document.write( "Good thing I am around, I think these people would allow themselves to starve to death. Its a holiday when the lilly is 1/2 the size of the pond? So is it a holiday when it covers the whole pond and they have all starved to death? LOL\r
\n" ); document.write( "\n" ); document.write( "1*2*2*2... or 2^0,2^1,2^2,2^3,...,2^45
\n" ); document.write( "it doubles its size every day, so 2^45 / 2 = 2^44
\n" ); document.write( "44 is the exponent, so 44 days after it first starts growing\r
\n" ); document.write( "\n" ); document.write( "The lilly will cover half the pond __44__ days after it first starts growing.
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