document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=274564>Question 274564</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have been asked to take some figures from a 'yield table' of trees. Specifically the trees per ha/ and the diameters. I  have then been asked to take the log base 10 of these figures, prior to plotting them on a graph. So in the first line (of many) I have 2309 trees with a diameter of 11   - what should I be doing with these figures. Am I to just move the decimal place?\r<BR>\n" );
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document.write( "Thanks\r<BR>\n" );
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document.write( "Kenton </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #200370 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=200370\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I have been asked to take some figures from a 'yield table' of trees. Specifically the trees per ha/ and the diameters. I have then been asked to take the log base 10 of these figures, prior to plotting them on a graph. So in the first line (of many) I have 2309 trees with a diameter of 11 - what should I be doing with these figures. Am I to just move the decimal place? <BR>\n" );
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document.write( "The log(base 10) of a number is the power of 10 required to express<BR>\n" );
document.write( "the number.<BR>\n" );
document.write( "For example log(base 10) of 10 = 1 because 10^1 = 10<BR>\n" );
document.write( "log(base 10) of 100 = 2 because 10^2 = 100<BR>\n" );
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document.write( "Your Problem requires a calculator (which you can find online).<BR>\n" );
document.write( "log(base 10) 2309 = 3.3634..<BR>\n" );
document.write( "log(base 10) 11 = 1.0414..<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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