document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=274594>Question 274594</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How would I solve this?    The gravitational force between two objects varies inversely as the square of the distance between the objects.  If a force of 25 pounds results from two objects that are 6 miles apart, how much force results from two objects that are 15 miles apart? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #200365 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=200365\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The gravitational force between two objects varies inversely as the square of the distance between the objects. If a force of 25 pounds results from two objects that are 6 miles apart, how much force results from two objects that are 15 miles apart?<BR>\n" );
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document.write( "F = k/r^2 (r is the distance)<BR>\n" );
document.write( "25 = k/6^2<BR>\n" );
document.write( "k = 900<BR>\n" );
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document.write( "F = 900/15^2 = 900/225<BR>\n" );
document.write( "F = 4 pounds<BR>\n" );
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document.write( "It's not necessary to solve for k:<BR>\n" );
document.write( "15 = 2.5*6<BR>\n" );
document.write( "F = 25/(2.5^2) = 25/6.25 (inverse square)<BR>\n" );
document.write( "F = 4 pounds<BR>\n" );
document.write( " </SPAN>\n" );
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