document.write( "Question 273880: how do solve log6x-3=-4 \n" ); document.write( "
Algebra.Com's Answer #200307 by jsmallt9(3758)\"\" \"About 
You can put this solution on YOUR website!
Is your problem
\n" ); document.write( "\"log%28%286x-3%29%29=-4\"
\n" ); document.write( "or
\n" ); document.write( "\"log%286%2C+%28x-3%29%29=-4\"
\n" ); document.write( "or
\n" ); document.write( "\"log%28%286x%29%29+-+3+=-4\"
\n" ); document.write( "or
\n" ); document.write( "\"log%286%2C+%28x%29%29+-+3+=-4\"?

\n" ); document.write( "Instead of me solving 4 equations, 3 of which you don't care about, please repost your problem using parentheses around the argument to the logarithm. And if the problem involves base 6 logarithms, just use something like:
\n" ); document.write( "base 6 log(x-3) = -4
\n" ); document.write( "or
\n" ); document.write( "log base 6 (x-3) = -4
\n" ); document.write( "
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