document.write( "Question 274474: James walked 4 mph for a certain amount of time and 3 mph for a certain amount of time. He went 27 miles.
\n" ); document.write( "Had he walked 3 mph faster throughout, he would have walked 51 miles. How long did he walk for 4 mph?\r
\n" ); document.write( "\n" ); document.write( "I feel like there is a variable missing, but my instructor says that there is not. I have tried this question 47 times. I don't have the answer to check if what I have is correct, but none of my work checks out. \r
\n" ); document.write( "\n" ); document.write( "I use
\n" ); document.write( "4(x) + 3(y) = 27
\n" ); document.write( "3(x-y)=51\r
\n" ); document.write( "\n" ); document.write( "My answer is 9 hours at 3 mph, and 6.75 at 4mph. If this is true, then why did they bother to give me the second part of the question. It wasn't even used.\r
\n" ); document.write( "\n" ); document.write( "Any help that can be offered is appreciated.
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Algebra.Com's Answer #200298 by scott8148(6628)\"\" \"About 
You can put this solution on YOUR website!
let x=\"4 mph time\" and y=\"3 mph time\"\r
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\n" ); document.write( "\n" ); document.write( "4x + 3y = 27 ___ 8x + 6y = 54\r
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\n" ); document.write( "\n" ); document.write( "(4 + 3)x + (3 + 3)y = 51 ___ 7x + 6y = 51\r
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\n" ); document.write( "\n" ); document.write( "subtracting equations ___ x = 3\r
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\n" ); document.write( "\n" ); document.write( "substituting ___ 4(3) + 3y = 27 ___ y = 5
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