document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=274169>Question 274169</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help! I am confused on how to work this problem.\r<BR>\n" );
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document.write( "Give the equation of a line perpendicular to the line y = -8x + 8 having the y-intercept 2 units below the y-intercept of the given equation. At what point the two equations cross each other?\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #200248 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=200248\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Give the equation of a line perpendicular to the line y = -8x + 8 having the y-intercept 2 units below the y-intercept of the given equation.<BR>\n" );
document.write( "Find the slope of perpendicular line (m1)<BR>\n" );
document.write( "The slope of the given equation is -8<BR>\n" );
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document.write( "m1 * -8 = -1; (the slope relationship between perpendicular lines)<BR>\n" );
document.write( "m1 = +<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F8 ALIGN=MIDDLE  ALT=\"1%2F8\"   DISABLED_style= \"max-width:90%; height:auto;\" > is the slope of the perpendicular line<BR>\n" );
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document.write( "The y intercept of this line = 6; (two units below the given equation)<BR>\n" );
document.write( "therefore:<BR>\n" );
document.write( "y = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F8 ALIGN=MIDDLE  ALT=\"1%2F8\"   DISABLED_style= \"max-width:90%; height:auto;\" >x + 6; the equation of the perpendicular line<BR>\n" );
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document.write( "At what point the two equations cross each other?<BR>\n" );
document.write( "When y's are equal, find x:<BR>\n" );
document.write( "-8x + 8 = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F8 ALIGN=MIDDLE  ALT=\"1%2F8\"   DISABLED_style= \"max-width:90%; height:auto;\" >x + 6 <BR>\n" );
document.write( "-8x = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F8 ALIGN=MIDDLE  ALT=\"1%2F8\"   DISABLED_style= \"max-width:90%; height:auto;\" >x + 6 -8<BR>\n" );
document.write( "-8x = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F8 ALIGN=MIDDLE  ALT=\"1%2F8\"   DISABLED_style= \"max-width:90%; height:auto;\" >x - 2 <BR>\n" );
document.write( "multiply by 8 to get rid of the denominator, results:<BR>\n" );
document.write( "-64x = x - 16<BR>\n" );
document.write( "-64x - x = -16<BR>\n" );
document.write( "-65x = -16<BR>\n" );
document.write( "x = +<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=16%2F65 ALIGN=MIDDLE  ALT=\"16%2F65\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "x = .246<BR>\n" );
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document.write( "Find y using the given equation<BR>\n" );
document.write( "y = -8(.246) + 8<BR>\n" );
document.write( "y = 6.03<BR>\n" );
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document.write( "Check in the other equation<BR>\n" );
document.write( "y = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F8 ALIGN=MIDDLE  ALT=\"1%2F8\"   DISABLED_style= \"max-width:90%; height:auto;\" >(.246) + 6<BR>\n" );
document.write( "y = 6.03<BR>\n" );
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document.write( "equations intersect at x=.246, y=6.03<BR>\n" );
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