document.write( "Question 33612: A box contains $17.70 in nickels, dimes, and quarters. The number of dimes is 8 less than twice the number of nickels. The number of quarters is 2 more than the sum of the number of nickels and dimes. How many coins of each kind are there in the box? \n" ); document.write( "
Algebra.Com's Answer #20024 by Paul(988)\"\" \"About 
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Numer of dimes = 2x-8
\n" ); document.write( "Nickels = x
\n" ); document.write( "Quarters = 2+(2x-8+x)
\n" ); document.write( "Total value x 100 = 1770
\n" ); document.write( "Nikel value x 100 = 5
\n" ); document.write( "Quarter value x 100 = 25
\n" ); document.write( "Dime value x 100 = 10
\n" ); document.write( "Equation:
\n" ); document.write( "5(x)+10(2x-8)+25(3x-6)=1770
\n" ); document.write( "5x+20x+75x-80-150=1770
\n" ); document.write( "100x=2000
\n" ); document.write( "x=20
\n" ); document.write( "2(20)-8=32
\n" ); document.write( "2+2(20)-8+20=54
\n" ); document.write( "Hence, there are 20 nickels, 54 quarters and 32 dimes.
\n" ); document.write( "Paul.
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