document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=274121>Question 274121</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If you had a see-saw(teeter-totter) that was 6 feet long and had a person weighting 200 pounds on one end and 100 pounds on the other.  Where would the fulcrum need to be so that their weight was equal? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #200211 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=200211\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> weight times length = weight times length\r<BR>\n" );
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document.write( "the fulcrum is 2 ft from the heavier person\r<BR>\n" );
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document.write( "200 * 2 = 100 * 4 </SPAN>\n" );
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