document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=274189>Question 274189</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I'm so confused, Im taking alebra online and don't even know where to start with this problem? 1 - 2/3y = 9/5- 1/5y + 3/5=(note the slashes I have between numbers are fractions. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #200117 by </B><A HREF=/tutors/aboutme.mpl?userid=calegebra><B>calegebra(14)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=calegebra><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=200117\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I will try to solve as it is written\r<BR>\n" );
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document.write( "1 - 2/3y = 9/5 - 1/5y + 3/5\r<BR>\n" );
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document.write( "first simplify fractions and move variables to left side of equation<BR>\n" );
document.write( "9/5 + 3/5 = 12/5 <BR>\n" );
document.write( "and<BR>\n" );
document.write( "-2/3y + 1/5y (must find common denominator which is 15)<BR>\n" );
document.write( "it becomes<BR>\n" );
document.write( "-10/15y + 3/15y = -7/15y\r<BR>\n" );
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document.write( "Now equation should look like this:\r<BR>\n" );
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document.write( "-7/15y = 12/5 - 1/1 (must find common denominator again Which is 15)<BR>\n" );
document.write( "then it looks like<BR>\n" );
document.write( "-7/15y = 36/15 - 15/15<BR>\n" );
document.write( "-7/15y = 21/15<BR>\n" );
document.write( "y = 21/15 divided by -7/15<BR>\n" );
document.write( "y = -3 </SPAN>\n" );
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