document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=33554>Question 33554</A>: <I><SPAN STYLE=\"word-break: break-all;\">  A regular pyramid has a triangular base with a base edge of 24 inches.  It's height is 36 inches.  What is the volume of the pyramid? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #20011 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=20011\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> VOLUME OF A REGULAR PYRAMID = (1/3)(BASE AREA)*(VERTICAL HEIGHT)<BR>\n" );
document.write( "BASE IS EQUILATERAL TRIANGLE WITH SIDE =24 \"<BR>\n" );
document.write( "SO AREA =(SIDE^2)SQRT(3)/4=24*24*SQRT(3)/4=144*SQRT(3)<BR>\n" );
document.write( "HEIGHT =36<BR>\n" );
document.write( "VOLUME =(1/3)*144*SQRT(3)*36=1728*SQRT(3) CUBIC INCHES. </SPAN>\n" );
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