document.write( "Question 274059: Given the graph below, how do I determin the rise, run, & slope? Also, how do I determine the equation so I can write it in standard form? \r
\n" ); document.write( "\n" ); document.write( "\"graph+%28600%2C600%2C-10%2C10%2C-10%2C10%2C%281%2F4%29%2Ax+%2B+2%29\"\r
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Algebra.Com's Answer #200071 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
I decide to put the equation in the form
\n" ); document.write( "\"y+=+mx+%2B+b\" where \"m\" is the slope
\n" ); document.write( "and \"b\" is the y-intercept
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\n" ); document.write( "First, I look at where the line crosses
\n" ); document.write( "the y-axis. It's at the point (0,2)
\n" ); document.write( "Plugging this into the general formula,
\n" ); document.write( "\"2+=+m%2A0+%2B+b\"
\n" ); document.write( "\"b+=+2\"
\n" ); document.write( "This is the y-intercept
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\n" ); document.write( "The easiest way to read off the slope is
\n" ); document.write( "from x-intercept to y-intercept or
\n" ); document.write( "from y-intercept to x-intercept
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\n" ); document.write( "Slope is change in y over change in x
\n" ); document.write( "Say I start at the x-intercept which is
\n" ); document.write( "at (-8,0) and I end at (0,2), the y-intercept
\n" ); document.write( "slope is \"%28y%5B2%5D+-+y%5B1%5D%29%2F%28x%5B2%5D+-+x%5B1%5D%29\"
\n" ); document.write( "which is \"%282+-+0%29%2F%280+-+%28-8%29%29+=+1%2F4\"
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\n" ); document.write( "Say I go in the other direction:
\n" ); document.write( "(0,2) to (-8,0)
\n" ); document.write( "The slope is \"%280+-+2%29%2F%28-8+-+0%29+=+1%2F4\"
\n" ); document.write( "I get the same answer as I should.
\n" ); document.write( "So, setting \"m+=+1%2F4\", the equation is
\n" ); document.write( "\"y+=+%281%2F4%29%2Ax+%2B+2\" Then put it in standard form
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