document.write( "Question 273973: twice as many dimes as nickles, two more quarters than nickels and a total of $5.50 \n" ); document.write( "
Algebra.Com's Answer #200043 by calegebra(14)![]() ![]() ![]() You can put this solution on YOUR website! set x = number of nickels \n" ); document.write( "2x = number of dimes \n" ); document.write( "x + 2 = number of quarters\r \n" ); document.write( "\n" ); document.write( "nickel = .05 \n" ); document.write( "dime = .10 \n" ); document.write( "quarter = .25\r \n" ); document.write( "\n" ); document.write( "(.05)(x) + (.10)(2x) + (.25)(x + 2) = $5.50 \n" ); document.write( ".05x + .20x + .25x + .50 = $5.50 \n" ); document.write( ".05x + .20x + .25x = $5.00 \n" ); document.write( ".50x = $5.00\r \n" ); document.write( "\n" ); document.write( "x = 10 number of nickels (10)(.05) = .50 \n" ); document.write( "2x = 20 number of dimes (20)(.10) = 2.00 \n" ); document.write( "x + 2 = 12 number of quarters (10 + 2) = 12 * .25 = 3.00\r \n" ); document.write( "\n" ); document.write( "Add them up 3.00 + 2.00 + .50 = 5.50 \n" ); document.write( " |