document.write( "Question 273973: twice as many dimes as nickles, two more quarters than nickels and a total of $5.50 \n" ); document.write( "
Algebra.Com's Answer #200043 by calegebra(14)\"\" \"About 
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set x = number of nickels
\n" ); document.write( "2x = number of dimes
\n" ); document.write( "x + 2 = number of quarters\r
\n" ); document.write( "\n" ); document.write( "nickel = .05
\n" ); document.write( "dime = .10
\n" ); document.write( "quarter = .25\r
\n" ); document.write( "\n" ); document.write( "(.05)(x) + (.10)(2x) + (.25)(x + 2) = $5.50
\n" ); document.write( ".05x + .20x + .25x + .50 = $5.50
\n" ); document.write( ".05x + .20x + .25x = $5.00
\n" ); document.write( ".50x = $5.00\r
\n" ); document.write( "\n" ); document.write( "x = 10 number of nickels (10)(.05) = .50
\n" ); document.write( "2x = 20 number of dimes (20)(.10) = 2.00
\n" ); document.write( "x + 2 = 12 number of quarters (10 + 2) = 12 * .25 = 3.00\r
\n" ); document.write( "\n" ); document.write( "Add them up 3.00 + 2.00 + .50 = 5.50
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