document.write( "Question 273975: y=x+1
\n" ); document.write( "2x+y=10
\n" ); document.write( "how do you solve this using substitution? \n" ); document.write( "

Algebra.Com's Answer #200026 by Tobiasz(54) $\"\"$ $\"About$

You can put this solution on YOUR website!
y=x+1
\n" ); document.write( "2x+y=10\r
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\n" ); document.write( "\n" ); document.write( "all you do is add part A into Part B , meaning plug it in and solve like a regular equation. \r
\n" ); document.write( "\n" ); document.write( "2x + x + 1 = 10\r
\n" ); document.write( "\n" ); document.write( "3x + 1 = 10 <--- one one from one and ten\r
\n" ); document.write( "\n" ); document.write( "3x = 9 <--- divide 3 from both sides\r
\n" ); document.write( "\n" ); document.write( " $\"x+=+3\"$ \r
\n" ); document.write( "\n" ); document.write( "2(3)+y=10\r
\n" ); document.write( "\n" ); document.write( "6 + y = 10 <-- minus 6 from both sides\r
\n" ); document.write( "\n" ); document.write( " $\"y+=+4\"$ \r
\n" ); document.write( "\n" ); document.write( "plug it in to check.!\r
\n" ); document.write( "\n" ); document.write( "2(3) + 4 = 10\r
\n" ); document.write( "\n" ); document.write( "6 + 4 = 10\r
\n" ); document.write( "\n" ); document.write( "10 = 10
\n" ); document.write( "CORRECT~!!\r
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