document.write( "Question 273812: 2logsqrt(x+10)=log6-(1/2)log9
\n" ); document.write( "please show me the steps to solve this.
\n" ); document.write( "

Algebra.Com's Answer #199982 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
2logsqrt(x+10)=log6-(1/2)log9
\n" ); document.write( "------
\n" ); document.write( "log[sqrt(x+10)]^2 = log[6] - log[9^(1/2)]
\n" ); document.write( "----
\n" ); document.write( "log(x+10) = log[6] - log[3]
\n" ); document.write( "---
\n" ); document.write( "log(x+10) = log[6/3]
\n" ); document.write( "---
\n" ); document.write( "log(x+10) = log[2]
\n" ); document.write( "---
\n" ); document.write( "x+10 = 2
\n" ); document.write( "x = -8
\n" ); document.write( "===============
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "
\n" );