document.write( "Question 273778: find 3 consecutive odd integers such that the square of the first increased by the product of the other two is 224 \n" ); document.write( "
Algebra.Com's Answer #199970 by ankor@dixie-net.com(22740)\"\" \"About 
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find 3 consecutive odd integers such that the square of the first increased by the product of the other two is 224
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\n" ); document.write( "\" 3 consecutive odd integers\"
\n" ); document.write( "x, (x+2), (x+4)
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\n" ); document.write( "\"such that the square of the first increased by the product of the other two is 224\"
\n" ); document.write( "x^2 + ((x+2)(x+4)) = 224
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\n" ); document.write( "x^2 + x^2 + 6x + 8 = 224
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\n" ); document.write( "2x^2 + 6x + 8 - 224 = 0
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\n" ); document.write( "2x^2 + 6x - 216 = 0
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\n" ); document.write( "Simplify, divide by 2
\n" ); document.write( "x^2 + 3x - 108 = 0
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\n" ); document.write( "Factors to
\n" ); document.write( "(x+12)(x-9) = 0
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\n" ); document.write( "positive solution
\n" ); document.write( "x = 9, the 1st odd integer
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\n" ); document.write( "Check using the integers, 9, 11, 13
\n" ); document.write( "9^2 + 11*13 =
\n" ); document.write( "81 = 143 = 224
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\n" ); document.write( "What about the solution x=-12? It satisfies the equation but,it's an even value\r
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