document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=273759>Question 273759</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I was wondering if this is right :) \r<BR>\n" );
document.write( "\n" );
document.write( "4. When a pizza restaurant’s delivery process is operating effectively, pizzas are delivered in an average of 						<BR>\n" );
document.write( "45 minutes with a standard deviation of 6 minutes. To monitor its delivery process, the restaurant randomly 						<BR>\n" );
document.write( "selects five pizzas each night and records their delivery times. For the sake of the argument, assume that the 						<BR>\n" );
document.write( "population of all delivery times on a given evening is normally distributed with a mean of µ = 45 minutes and a standard deviation of &#948; = 6 minutes. 						\r<BR>\n" );
document.write( "\n" );
document.write( "z= X - mean/standard deviation = 5-45/6=-6.66<BR>\n" );
document.write( "			The area between z=0 and z=-6.66-= how do i find the area?? do I double 3?			\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #199956 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=199956\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 4. When a pizza restaurant’s delivery process is operating effectively, pizzas are delivered in an average of 45 minutes with a standard deviation of 6 minutes. \r<BR>\n" );
document.write( "\n" );
document.write( "To monitor its delivery process, the restaurant randomly selects five pizzas each night and records their delivery times.<BR>\n" );
document.write( " <BR>\n" );
document.write( "For the sake of the argument, assume that the population of all delivery times on a given evening is normally distributed with a mean of µ = 45 minutes and a standard deviation of &#948; = 6 minutes.<BR>\n" );
document.write( "-------<BR>\n" );
document.write( "Comment: You need to be given the mean delivery time for the t pizzas.<BR>\n" );
document.write( "Then you need to find the t-value for that sample mean time using<BR>\n" );
document.write( "t(x-bar) = (xbar-45)/[6/sqrt(5)]<BR>\n" );
document.write( "----<BR>\n" );
document.write( "Comment: IF the alternate hypothis is \"u is not equal to 45\", the p-value<BR>\n" );
document.write( "for your problem is 2*P(t > the t-value you obtained for x-bar)<BR>\n" );
document.write( "---------------------------------------------------<BR>\n" );
document.write( " 						\r<BR>\n" );
document.write( "\n" );
document.write( "z= (X - mean)/standard deviation = 5-45/6=-6.66<BR>\n" );
document.write( "Comment (5-45) is incorrect.  5 is the sample size; 45 is the expected<BR>\n" );
document.write( "dilivery time.  You need t(x-bar-45) where x-bar is the sample's mean<BR>\n" );
document.write( "time.<BR>\n" );
document.write( "=========================\r<BR>\n" );
document.write( "\n" );
document.write( "The area between z=0 and z=-6.66-= how do i find the area?? do I double <BR>\n" );
document.write( "Comment: I'm not sure where you are going with with question. You don't<BR>\n" );
document.write( "need the area (which is 0.5000).  The doubling is associated with a p-score<BR>\n" );
document.write( "for a two-tail test.<BR>\n" );
document.write( "============================<BR>\n" );
document.write( "Let me know if you need more help on this problem.<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.		\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );