document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=273745>Question 273745</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the perimeter of a rectangular yard is 270 feet. if its length is 25 feet greater than its width, what are the dimensions of the yard. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #199942 by </B><A HREF=/tutors/aboutme.mpl?userid=CharlesG2><B>CharlesG2(834)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CharlesG2><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=199942\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the perimeter of a rectangular yard is 270 feet. if its length is 25 feet greater than its width, what are the dimensions of the yard.\r<BR>\n" );
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document.write( "P perimeter = 2 * L length + 2 * W width = 270 feet<BR>\n" );
document.write( "270 = 2 * (L + W)<BR>\n" );
document.write( "135 = L + W<BR>\n" );
document.write( "135 = (W + 25) + W<BR>\n" );
document.write( "135 = 2W + 25<BR>\n" );
document.write( "110 = 2W<BR>\n" );
document.write( "55 feet = W<BR>\n" );
document.write( "L = W + 25 = 55 + 25 = 80 feet<BR>\n" );
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