document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=33597>Question 33597</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How can i solve by completing the square? I know a bit how but i just need some help!\r<BR>\n" );
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document.write( "X^2-X-1=0\r<BR>\n" );
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document.write( "X^2-X=1\r<BR>\n" );
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document.write( "X^2-x/2=1/2\r<BR>\n" );
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document.write( "X^2-x/2+(-1/4)^2=1/2+(-1/4)^2\r<BR>\n" );
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document.write( "I get lost here can some one help me solve or make any corrections THNX! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #19993 by </B><A HREF=/tutors/aboutme.mpl?userid=Nate><B>Nate(3500)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Nate><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=19993\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I will copy and correct your problem:\r<BR>\n" );
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document.write( "X^2-X-1=0\r<BR>\n" );
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document.write( "X^2-X=1 add one\r<BR>\n" );
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document.write( "(x-(1/2))^2=1+(1/4) take half of 1 and square that to add to other side\r<BR>\n" );
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document.write( "(x-(1/2))^2=(5/4) simplify\r<BR>\n" );
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document.write( "x-(1/2)=+ or -((5)^(1/2))/2 square root to get a positive and negative\r<BR>\n" );
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document.write( "x=(1/2)+((5)^(1/2))/2) or x=(1/2)-((5)^(1/2))/2) and (1/2)\r<BR>\n" );
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document.write( "your answer:<BR>\n" );
document.write( "x=(1/2)+((5)^(1/2))/2) or x=(1/2)-((5)^(1/2))/2) </SPAN>\n" );
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