document.write( "Question 273613: find all complex numbers that are solution of give equation the answer leave in a + bi
\n" ); document.write( "z^8 - 16 = 0 \n" ); document.write( "
Algebra.Com's Answer #199916 by CharlesG2(834)\"\" \"About 
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find all complex numbers that are solution of give equation the answer leave in a + bi
\n" ); document.write( "z^8 - 16 = 0\r
\n" ); document.write( "\n" ); document.write( "z^8 = 16
\n" ); document.write( "z^4 = 4 or -4
\n" ); document.write( "z^2 = +- 2 or +- 2i
\n" ); document.write( "(2*2=4, -2*-2=4)
\n" ); document.write( "(sqrt(4 * -1)=2i)
\n" ); document.write( "(2i * 2i = 4i^2 = 4 * -1 = -4)
\n" ); document.write( "(-2i * -2i = 4i^2 = 4 * -1 = -4)
\n" ); document.write( "z = +- sqrt(2) or +- sqrt(-2) or +- sqrt(2i) or +- sqrt(-2i)
\n" ); document.write( "(sqrt(2) * sqrt(2) = 2)
\n" ); document.write( "(-sqrt(2) * -sqrt(2) = 2)
\n" ); document.write( "z = +- sqrt(2) or +- sqrt(2)*i or +- sqrt(2i) or +- sqrt(-2i)
\n" ); document.write( "(sqrt(2)*i*sqrt(2)*i = 2 * -1 = -2)
\n" ); document.write( "(-sqrt(2)*i*-sqrt(2)*i = 2 * -1 = -2)
\n" ); document.write( "(sqrt(2i) * sqrt(2i) = 2i)
\n" ); document.write( "(-sqrt(2i) * -sqrt(2i) = 2i)
\n" ); document.write( "(sqrt(-2i) * sqrt(-2i) = -2i)
\n" ); document.write( "(-sqrt(-2i) * -sqrt(-2i) = -2i)
\n" ); document.write( "z = +- sqrt(2) or +- sqrt(2)*i or +- sqrt(2i) or +- sqrt(-2i)
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