document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=33602>Question 33602</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Let y vary inversely as x. If x = 2.6hen y = 5, what is y when x = 3.25 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #19991 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=19991\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> inversely means y=k/x.<BR>\n" );
document.write( "We need to determine \"k\".<BR>\n" );
document.write( "If x=2 then y=5, therefore 5=k/2<BR>\n" );
document.write( "So, k=10<BR>\n" );
document.write( "EQUATION:<BR>\n" );
document.write( "y=10/x<BR>\n" );
document.write( "If x=3.25, find y.<BR>\n" );
document.write( "y=10/3.25<BR>\n" );
document.write( "y= 3.08<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );