document.write( "Question 273690: JACK USUALLY MOWS HIS LAWN IN 6 HOURS. MARYILYN CAN MOW THE SAME YARD IN 5 HOURS. HOW MUCH TIME WOULD IT TAKE THEM TO MOW THE LAWN TOGETHER? \n" ); document.write( "
Algebra.Com's Answer #199909 by stanbon(75887)\"\" \"About 
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JACK USUALLY MOWS HIS LAWN IN 6 HOURS. MARYILYN CAN MOW THE SAME YARD IN 5 HOURS. HOW MUCH TIME WOULD IT TAKE THEM TO MOW THE LAWN TOGETHER?
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\n" ); document.write( "Jack's rate: 1/6 job/hr
\n" ); document.write( "Marilyn rate: 1/5 job/hr
\n" ); document.write( "Together rate: 1/x job/hr
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\n" ); document.write( "Equation:
\n" ); document.write( "rate + rate = together rate
\n" ); document.write( "1/6 + 1/5 = 1/x
\n" ); document.write( "Multiply thru by 30x
\n" ); document.write( "5x + 6x = 30
\n" ); document.write( "11x = 30
\n" ); document.write( "x = 30/11 = 2.73 hrs
\n" ); document.write( "0.73hr = 0.73(60 minutes) = 43.8 minutes
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\n" ); document.write( "Ans: 2 hr and 44 minutes
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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