document.write( "Question 273690: JACK USUALLY MOWS HIS LAWN IN 6 HOURS. MARYILYN CAN MOW THE SAME YARD IN 5 HOURS. HOW MUCH TIME WOULD IT TAKE THEM TO MOW THE LAWN TOGETHER? \n" ); document.write( "
Algebra.Com's Answer #199909 by stanbon(75887) ![]() You can put this solution on YOUR website! JACK USUALLY MOWS HIS LAWN IN 6 HOURS. MARYILYN CAN MOW THE SAME YARD IN 5 HOURS. HOW MUCH TIME WOULD IT TAKE THEM TO MOW THE LAWN TOGETHER? \n" ); document.write( "----------------- \n" ); document.write( "Jack's rate: 1/6 job/hr \n" ); document.write( "Marilyn rate: 1/5 job/hr \n" ); document.write( "Together rate: 1/x job/hr \n" ); document.write( "------------------------------ \n" ); document.write( "Equation: \n" ); document.write( "rate + rate = together rate \n" ); document.write( "1/6 + 1/5 = 1/x \n" ); document.write( "Multiply thru by 30x \n" ); document.write( "5x + 6x = 30 \n" ); document.write( "11x = 30 \n" ); document.write( "x = 30/11 = 2.73 hrs \n" ); document.write( "0.73hr = 0.73(60 minutes) = 43.8 minutes \n" ); document.write( "------ \n" ); document.write( "Ans: 2 hr and 44 minutes \n" ); document.write( "=============================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |