document.write( "Question 273304: The surface area of a cube is 24 cm2. what is the new surface area of the cube if the length of each edge of the cube is tripled. \n" ); document.write( "
Algebra.Com's Answer #199865 by colliefan(242)\"\" \"About 
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Let's start by finding the length of the edge of the initial cube. A cube has 6 different surfaces that are all squares that have the same length and widths and so have the same areas. The surface area of the cube must be 6 * the area of one square because there are six surfaces. As an equation, if S is surface area and a is area of one square: s=6a.\r
\n" ); document.write( "\n" ); document.write( "We know that s=24 cm^2 for the initial cube. Putting that in to the equation,
\n" ); document.write( "24=6a
\n" ); document.write( "24/6=6a/6
\n" ); document.write( "4=a\r
\n" ); document.write( "\n" ); document.write( "Now we know the area of one square to be 4 cm^2. If the area of the square is 4 cm^2, the length of one side must be 2 since the area of a square is the length squared. a=l^2
\n" ); document.write( "4=l^2
\n" ); document.write( "2=l\r
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\n" ); document.write( "\n" ); document.write( "If the initial length is 2, tripling it gives a square with length 6. The area of a square with length 6 is 6^2 or 36. The surface area of the cube made up of such squares is 6*36 or 216.\r
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