document.write( "Question 273512: The perimeter of a rectangular field is 606 m. the length is 42 m more than twice the width. \n" ); document.write( "
Algebra.Com's Answer #199842 by bobdabuildr(27)![]() ![]() ![]() You can put this solution on YOUR website! P=2L+2W\r \n" ); document.write( "\n" ); document.write( "Let x=width , and let 42+2x=length\r \n" ); document.write( "\n" ); document.write( "606=2x+2(42+2x) \n" ); document.write( "606=2x+84+4x \n" ); document.write( "606=6x+84 \n" ); document.write( "606-84=6x+84-84 Subtract 84 from both sides \n" ); document.write( "522=6x \n" ); document.write( "87=x Divide both sides by 6\r \n" ); document.write( "\n" ); document.write( "Now plug in the answer for x to get your lenght, 42+2(87)=216\r \n" ); document.write( "\n" ); document.write( "Check\r \n" ); document.write( "\n" ); document.write( "606=2(87)+2(216) \n" ); document.write( "606=174+432 \n" ); document.write( "606=606 \n" ); document.write( " |