document.write( "Question 273512: The perimeter of a rectangular field is 606 m. the length is 42 m more than twice the width. \n" ); document.write( "
Algebra.Com's Answer #199842 by bobdabuildr(27)\"\" \"About 
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P=2L+2W\r
\n" ); document.write( "\n" ); document.write( "Let x=width , and let 42+2x=length\r
\n" ); document.write( "\n" ); document.write( "606=2x+2(42+2x)
\n" ); document.write( "606=2x+84+4x
\n" ); document.write( "606=6x+84
\n" ); document.write( "606-84=6x+84-84 Subtract 84 from both sides
\n" ); document.write( "522=6x
\n" ); document.write( "87=x Divide both sides by 6\r
\n" ); document.write( "\n" ); document.write( "Now plug in the answer for x to get your lenght, 42+2(87)=216\r
\n" ); document.write( "\n" ); document.write( "Check\r
\n" ); document.write( "\n" ); document.write( "606=2(87)+2(216)
\n" ); document.write( "606=174+432
\n" ); document.write( "606=606
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