document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=273554>Question 273554</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A company manufactures both liquid crystal display (LCD) and cathode ray tube (CRT) color monitors. The cost of materials for a CRT monitor is $30, whereas the cost of materials for an LCD monitor is $130. The cost of labor to manufacture a CRT monitor is $80, whereas the cost of labor to manufacture an LCD monitor is $130. During a week when the company has budgeted $7910 for materials and $10260 for labor, how many LCD monitors does the company plan to manufacture? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #199826 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=199826\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> cost of CRT materials = $30<BR>\n" );
document.write( "cost of LCD materials = $130<BR>\n" );
document.write( "cost of CRT labor = $80<BR>\n" );
document.write( "cost of LCD labor = $130<BR>\n" );
document.write( "total cost of materials = $7910<BR>\n" );
document.write( "total cost of labor = 10260\r<BR>\n" );
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document.write( "let x = number of CRT<BR>\n" );
document.write( "let y = numbe4r of LCD\r<BR>\n" );
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document.write( "equation for material is:\r<BR>\n" );
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document.write( "30x + 130y = 7910\r<BR>\n" );
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document.write( "equation for labor is:\r<BR>\n" );
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document.write( "80x + 130y = 10260\r<BR>\n" );
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document.write( "you need to solve these 2 equations to get your answer.\r<BR>\n" );
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document.write( "the equations are:\r<BR>\n" );
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document.write( "                     30x + 130y = 7910\r\n" );
document.write( "                     80x + 130y = 10260\r\n" );
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document.write( "subtract first equation from second to get:\r<BR>\n" );
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document.write( "50x = 2350\r<BR>\n" );
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document.write( "divide both sides of this equation by 50 to get:\r<BR>\n" );
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document.write( "x = 47\r<BR>\n" );
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document.write( "substitute for x in first equation to get:\r<BR>\n" );
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document.write( "30x + 130y = 7910 becomes:<BR>\n" );
document.write( "30*47 + 130y = 7910 which becomes:<BR>\n" );
document.write( "1410 + 130y = 7910<BR>\n" );
document.write( "subtract 1410 from both sides to get:<BR>\n" );
document.write( "130y = 7910 - 1410<BR>\n" );
document.write( "combine like terms to get:<BR>\n" );
document.write( "130y = 6500<BR>\n" );
document.write( "divide both sides by 130 to get:<BR>\n" );
document.write( "y = 50\r<BR>\n" );
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document.write( "you have x = 47 and y = 50\r<BR>\n" );
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document.write( "substitute in both original equations to see that these values solve both of them at the same time.\r<BR>\n" );
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document.write( "original equations are:\r<BR>\n" );
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document.write( "                     30x + 130y =  7910\r\n" );
document.write( "                     80x + 130y = 10260\r\n" );
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document.write( "after substitution they become:\r<BR>\n" );
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document.write( "                     30*47  + 130*50  =  7910\r\n" );
document.write( "                     80*47  + 130*50  = 10260\r\n" );
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document.write( "simplify to get:\r<BR>\n" );
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document.write( "                     1410  + 6500  =  7910\r\n" );
document.write( "                     3760  + 6500  = 10260\r\n" );
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document.write( "both these equations are true confirming the values for x and y are good.\r<BR>\n" );
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document.write( "x is the number of CRT<BR>\n" );
document.write( "y is the number of LCD\r<BR>\n" );
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document.write( "answer to the question is that 50 LCD monitors are being planned to be manufactured during a week that the company has budgeted 7910 for materials and 10260 for labor.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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