document.write( "Question 273568: how do you write this as an equation?
\n" ); document.write( "seven more than the product of six and a number is eight less than the product of three and a number.
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Algebra.Com's Answer #199820 by Theo(13342)\"\" \"About 
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let x be the first number
\n" ); document.write( "let y be the second number.
\n" ); document.write( "if they're the same number, then you make y = x.\r
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\n" ); document.write( "\n" ); document.write( "assuming the numbers are different, then:\r
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\n" ); document.write( "\n" ); document.write( "6x + 7 = 3y - 8\r
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\n" ); document.write( "\n" ); document.write( "assuming the numbers are the same, then:\r
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\n" ); document.write( "\n" ); document.write( "6x + 7 = 3x - 8\r
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\n" ); document.write( "\n" ); document.write( "assuming they're the same number, I would solve this to get:\r
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\n" ); document.write( "\n" ); document.write( "6x + 7 = 3x - 8
\n" ); document.write( "subtract 7 from both sides of this equation and subtract 3x from both sides of this equation to get:
\n" ); document.write( "6x - 3x = -8 - 7
\n" ); document.write( "combine like terms to get:
\n" ); document.write( "3x = -15
\n" ); document.write( "divide both sides by 3 to get:
\n" ); document.write( "x = -5\r
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\n" ); document.write( "\n" ); document.write( "assuming the number is -5, then:\r
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\n" ); document.write( "\n" ); document.write( "6*-5 + 7 = 3*-5 - 8
\n" ); document.write( "simplify to get:
\n" ); document.write( "-30+7 = -15-8
\n" ); document.write( "combine like terms to get:
\n" ); document.write( "-23 = -23\r
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\n" ); document.write( "\n" ); document.write( "equation is satisfied.\r
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\n" ); document.write( "\n" ); document.write( "number is -5\r
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\n" ); document.write( "\n" ); document.write( "the product of 6 and the number is -30
\n" ); document.write( "seven more than that is -23\r
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\n" ); document.write( "\n" ); document.write( "the product of 3 and the number is -15
\n" ); document.write( "8 less than that is -23.\r
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