document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=33600>Question 33600</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I know this is  the answer for 2X^2-3X+1=0. But if it were to be left irrational root in simplest form would this be it?\r<BR>\n" );
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document.write( "3(+-)Sqrt 1 / 4 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #19982 by </B><A HREF=/tutors/aboutme.mpl?userid=priya><B>priya(51)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=priya><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=19982\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  2x^2 -3x+1 = 0<BR>\n" );
document.write( " the value of x can be found by factoring,\r<BR>\n" );
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document.write( "  that gives u (2x-1)(x-1) =0\r<BR>\n" );
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document.write( "    therefore x=1/2 and 1.\r<BR>\n" );
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document.write( "PRIYA </SPAN>\n" );
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