document.write( "Question 273579: Fred and Wilma start on a hike at 4 mi/hr. Three hours later barney discovers that they had forgotten their lunch and started after them on his bike at 12 mi/hr. How far had Fred and Wilma traveled when Barney caught up with them? \n" ); document.write( "
Algebra.Com's Answer #199819 by mananth(16949)\"\" \"About 
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Fred and Wilma start on a hike at 4 mi/hr. Three hours later barney discovers that they had forgotten their lunch and started after them on his bike at 12 mi/hr. How far had Fred and Wilma traveled when Barney caught up with them?\r
\n" ); document.write( "\n" ); document.write( "fred and wilma have traveled 12 miles in three hours when barney starts\r
\n" ); document.write( "\n" ); document.write( "Let the distance at which they meet be x\r
\n" ); document.write( "\n" ); document.write( "x-12 is the distance fred & wilma travel after barney starts & meets them.\r
\n" ); document.write( "\n" ); document.write( "Distance traveled by barney is x\r
\n" ); document.write( "\n" ); document.write( "time taken by fred & wilma is x-12/ 3\r
\n" ); document.write( "\n" ); document.write( "time taken by barney is x/12\r
\n" ); document.write( "\n" ); document.write( "But these two times are same\r
\n" ); document.write( "\n" ); document.write( "x-12/3 = x/12\r
\n" ); document.write( "\n" ); document.write( "12(x-1
\n" ); document.write( "12x-144=3x2)=3x\r
\n" ); document.write( "\n" ); document.write( "12x-3x=144
\n" ); document.write( "9x=144\r
\n" ); document.write( "\n" ); document.write( "x=16\r
\n" ); document.write( "\n" ); document.write( "fred and wilma have traveled 12+16 miles when Barney catches up.\r
\n" ); document.write( "\n" ); document.write( "x=16\r
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