document.write( "Question 273579: Fred and Wilma start on a hike at 4 mi/hr. Three hours later barney discovers that they had forgotten their lunch and started after them on his bike at 12 mi/hr. How far had Fred and Wilma traveled when Barney caught up with them? \n" ); document.write( "
Algebra.Com's Answer #199819 by mananth(16949) You can put this solution on YOUR website! Fred and Wilma start on a hike at 4 mi/hr. Three hours later barney discovers that they had forgotten their lunch and started after them on his bike at 12 mi/hr. How far had Fred and Wilma traveled when Barney caught up with them?\r \n" ); document.write( "\n" ); document.write( "fred and wilma have traveled 12 miles in three hours when barney starts\r \n" ); document.write( "\n" ); document.write( "Let the distance at which they meet be x\r \n" ); document.write( "\n" ); document.write( "x-12 is the distance fred & wilma travel after barney starts & meets them.\r \n" ); document.write( "\n" ); document.write( "Distance traveled by barney is x\r \n" ); document.write( "\n" ); document.write( "time taken by fred & wilma is x-12/ 3\r \n" ); document.write( "\n" ); document.write( "time taken by barney is x/12\r \n" ); document.write( "\n" ); document.write( "But these two times are same\r \n" ); document.write( "\n" ); document.write( "x-12/3 = x/12\r \n" ); document.write( "\n" ); document.write( "12(x-1 \n" ); document.write( "12x-144=3x2)=3x\r \n" ); document.write( "\n" ); document.write( "12x-3x=144 \n" ); document.write( "9x=144\r \n" ); document.write( "\n" ); document.write( "x=16\r \n" ); document.write( "\n" ); document.write( "fred and wilma have traveled 12+16 miles when Barney catches up.\r \n" ); document.write( "\n" ); document.write( "x=16\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |