document.write( "Question 273600: In a chemistry class, 6 liters of a 12% alcohol solution must be mixed with a 20% solution to get a 14% solution. How many liters of the 20% solution are needed? \n" ); document.write( "
Algebra.Com's Answer #199815 by mananth(16946)\"\" \"About 
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In a chemistry class, 6 liters of a 12% alcohol solution must be mixed with a 20% solution to get a 14% solution. How many liters of the 20% solution are needed?\r
\n" ); document.write( "\n" ); document.write( "Let the quantity of 20% solution be x liters\r
\n" ); document.write( "\n" ); document.write( "12%------------------20%-------------------14% mix\r
\n" ); document.write( "\n" ); document.write( "6-------------------- x--------------------x+6 (quantity)\r
\n" ); document.write( "\n" ); document.write( "Form an equation with actual parts mixed\r
\n" ); document.write( "\n" ); document.write( "0.12*6 + 0.2 x = 0.14(x+6)\r
\n" ); document.write( "\n" ); document.write( "0.72+0.2x = 0.14x+0.84\r
\n" ); document.write( "\n" ); document.write( "0.2x-0.14x=0.84-0.72\r
\n" ); document.write( "\n" ); document.write( "0.06x=0.12\r
\n" ); document.write( "\n" ); document.write( "x=2 liters which is the quantity of 20% alcohol required\r
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