document.write( "Question 273593: Molly's Custom Kitchen Supplies sells handmade forks and spoons. It cost the store $1.70 to buy the supplies to make a fork and $1.30 to buy the supplies to make a spoon. The store sells forks for $5.60 and spoons for $5.40. Last April Molly's Custom Kitchen Supplies spent $37.90 on materials for forks and spoons. They sold the finished products for a total of $147.20. How many forks and how many spoons did they make last April? \n" ); document.write( "
Algebra.Com's Answer #199810 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
let x = number of forks
\n" ); document.write( "let y = number of spoons\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "cost of a fork = 1.70
\n" ); document.write( "cost of a spoon = 1.30\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "revenue from a fork = 5.60
\n" ); document.write( "revenue from a spoon = 5.40\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "In april they spent 37.90 on material.
\n" ); document.write( "They sold them for a total of 147.20\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "your cost equation is:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "1.70 * x + 1.30 * y = 37.90\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "your revenue equation is:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "5.60 * x + 5.40 * y = 147.20\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "solve these two equations simultaneously to get your answer.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "simultaneously means the same value of x and the same value of y solve both equations at the same time.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "your two equations are:\r
\n" ); document.write( "\n" ); document.write( "
\r\n" );
document.write( "                  1.70 * x + 1.30 * y = 37.90\r\n" );
document.write( "                  5.60 * x + 5.40 * y = 147.20\r\n" );
document.write( "

\n" ); document.write( "multiply the first equation by 5.6 and multiply the second equation by 1.7 to get:\r
\n" ); document.write( "\n" ); document.write( "
\r\n" );
document.write( "                  9.52 * x + 7.28 * y = 212.24\r\n" );
document.write( "                  9.52 * x + 9.18 * y = 250.24\r\n" );
document.write( "

\n" ); document.write( "subtract the first equation from the second equation to get:\r
\n" ); document.write( "\n" ); document.write( "
\r\n" );
document.write( "                             1.9 * y = 38\r\n" );
document.write( "

\n" ); document.write( "divide both sides of this equation by 1.9 to get:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "y = 20\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "substitute that value for y in the first original equation.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "first original equation is:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "1.70 * x + 1.30 * y = 37.90\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "substitute 20 for y to get:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "1.70 * x + 1.30 * 20 = 37.90 which becomes:
\n" ); document.write( "1.70 * x + 26 = 37.90
\n" ); document.write( "subtract 26 from both sides of this equation to get:
\n" ); document.write( "1.70 * x = 37.90 - 26 which becomes:
\n" ); document.write( "1.70 * x = 11.90
\n" ); document.write( "divide both sides of this equation by 1.7 to get:
\n" ); document.write( "x = 11.90 / 1.7 = 7\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "you have:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "x = 7
\n" ); document.write( "y = 20\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "substitute these values into the original equations to confirm they are good.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "the original equations are:\r
\n" ); document.write( "\n" ); document.write( "
\r\n" );
document.write( "                  1.70 * x + 1.30 * y = 37.90\r\n" );
document.write( "                  5.60 * x + 5.40 * y = 147.20\r\n" );
document.write( "

\n" ); document.write( "substituting 20 for x and 7 for y, these equations become:\r
\n" ); document.write( "\n" ); document.write( "
\r\n" );
document.write( "                  1.70 * 7 + 1.30 * 20 = 37.90\r\n" );
document.write( "                  5.60 * 7 + 5.40 * 20 = 147.20\r\n" );
document.write( "

\n" ); document.write( "after simplification, these equations become:\r
\n" ); document.write( "\n" ); document.write( "
\r\n" );
document.write( "                  11.9 +  26 =  37.90\r\n" );
document.write( "                  39.2 + 108 + 147.20\r\n" );
document.write( "

\n" ); document.write( "both equations are true so the value for x and y are good.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "those values are:
\n" ); document.write( "x = 7
\n" ); document.write( "y = 20\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "they made 7 forks and 20 spoons.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );