document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=273586>Question 273586</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if an angle is 30 more than one half of its complement, find the measure  of the angle </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #199804 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=199804\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let one angle be x\r<BR>\n" );
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document.write( "the compliment will be 90-x\r<BR>\n" );
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document.write( "half the compliment = 1/2 * (90-x)\r<BR>\n" );
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document.write( "x = 1/2*(90-x)+30\r<BR>\n" );
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document.write( "x =1/2 *90 - 1/2 *x +30\r<BR>\n" );
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document.write( "x =45 -1/2 *x +30\r<BR>\n" );
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document.write( "3x/2 = 75\r<BR>\n" );
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document.write( "3x = 150<BR>\n" );
document.write( "x=50\r<BR>\n" );
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