document.write( "Question 273545: A student has money in three accounts that pay 5%, 7%, and 8% in annual interest. She has three times as much invested at 8% as she does at 5%. If the total amount she has invested is $2,700 and her interest for the year comes to $194, how much money does she have in each account? \n" ); document.write( "
Algebra.Com's Answer #199791 by mananth(16946)\"\" \"About 
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A student has money in three accounts that pay 5%, 7%, and 8% in annual interest. She has three times as much invested at 8% as she does at 5%. If the total amount she has invested is $2,700 and her interest for the year comes to $194, how much money does she have in each account?\r
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\n" ); document.write( "\n" ); document.write( "Let the student invest x amount in 5 % \r
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\n" ); document.write( "\n" ); document.write( "5%------------7%-----------------8% --------- Total\r
\n" ); document.write( "\n" ); document.write( "x-------2700-(x+3x)--------------3x--------- 2700 Invested amount\r
\n" ); document.write( "\n" ); document.write( "The sum of all the 3 interests = 194\r
\n" ); document.write( "\n" ); document.write( "0.05x + 0.07* 2700-(x+3x)+ 0.08*3x = 194\r
\n" ); document.write( "\n" ); document.write( "0.05x +0.07*( 2700 -x-3x) +0.08*3x =194\r
\n" ); document.write( "\n" ); document.write( "0.05x + 189-0.28x + 0.24x=194\r
\n" ); document.write( "\n" ); document.write( "0.08x =194-189\r
\n" ); document.write( "\n" ); document.write( "x= 5/0.01\r
\n" ); document.write( "\n" ); document.write( "x= 500 in 5% account\r
\n" ); document.write( "\n" ); document.write( "3x = 1500 in 8 % account\r
\n" ); document.write( "\n" ); document.write( "2700-(500+1500) = 700 in 7 % account \r
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