document.write( "Question 33580This question is from textbook
\n" ); document.write( ": 6y squared + 12y +13 = 2y squared + 4 \n" ); document.write( "
Algebra.Com's Answer #19978 by priya(51)\"\" \"About 
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the given equation is
\n" ); document.write( " 6y^2 + 12y +13 = 2y^2 +4\r
\n" ); document.write( "\n" ); document.write( "this can be written as,\r
\n" ); document.write( "\n" ); document.write( " 6y^2 +12y +13 -2y^2 -4 = 0 (by bringing the variable and numbers on the right to
\n" ); document.write( " the left)\r
\n" ); document.write( "\n" ); document.write( " 4y^2 +12y +9 = 0
\n" ); document.write( "simplify this by factoring\r
\n" ); document.write( "\n" ); document.write( " we get, (2y +3)(2y+3) = 0\r
\n" ); document.write( "\n" ); document.write( "therefore the values of y are 2y+3 =0
\n" ); document.write( " y = -3/2 ,-3/2\r
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\n" ); document.write( "PRIYA
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