document.write( "Question 273089: The area of a rectangle is 12sq. units and the diagonal of the rectangle has a length of 2 then the square root and underneath that is a 10. Find the perimeter of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #199739 by ankor@dixie-net.com(22740)\"\" \"About 
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The area of a rectangle is 12sq. units and the diagonal of the rectangle has a length of 2 then the square root and underneath that is a 10.
\n" ); document.write( " Find the perimeter of the rectangle?
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\n" ); document.write( "Area = 12 sq/units; Diagonal = \"2sqrt%2810%29\"
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\n" ); document.write( "Find legs of the right triangle; a^2 + b^2 = c^2
\n" ); document.write( "\"sqrt%28L%5E2+%2B+W%5E2%29\" = \"2sqrt%2810%29\"
\n" ); document.write( "\"sqrt%28L%5E2+%2B+W%5E2%29\" = \"sqrt%284%2A10%29\"
\n" ); document.write( "\"sqrt%28L%5E2+%2B+W%5E2%29\" = \"sqrt%2840%29\"
\n" ); document.write( " square both sides
\n" ); document.write( "L^2 + W^2 = 40
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\n" ); document.write( "The area equation
\n" ); document.write( "L*W = 12
\n" ); document.write( "L = \"12%2FW\"; for substitution below
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\n" ); document.write( "\"%2812%2FW%29%5E2\" + W^2 = 40
\n" ); document.write( "\"%28144%2FW%5E2%29\" + W^2 = 40
\n" ); document.write( "multiply equation by W^2
\n" ); document.write( "144 + W^4 = 40W^2
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\n" ); document.write( "A quadratic equation
\n" ); document.write( "W^4 - 40W^2 + 144 = 0
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\n" ); document.write( "this will factor
\n" ); document.write( "(W^2 - 36)(W^2 - 4) = 0
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\n" ); document.write( "Two solutions
\n" ); document.write( "W^2 = 36
\n" ); document.write( "W = 6, call this one the length
\n" ); document.write( "and
\n" ); document.write( "W^2 = 4
\n" ); document.write( "W = 2, the width
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\n" ); document.write( "P = 2(6) + 2(2)
\n" ); document.write( "P = 12 + 4
\n" ); document.write( "P = 16 units is the perimeter
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\n" ); document.write( "A = 6*2 = 12 confirm using the area
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