document.write( "Question 273089: The area of a rectangle is 12sq. units and the diagonal of the rectangle has a length of 2 then the square root and underneath that is a 10. Find the perimeter of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #199739 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! The area of a rectangle is 12sq. units and the diagonal of the rectangle has a length of 2 then the square root and underneath that is a 10. \n" ); document.write( " Find the perimeter of the rectangle? \n" ); document.write( ": \n" ); document.write( "Area = 12 sq/units; Diagonal = \n" ); document.write( ": \n" ); document.write( "Find legs of the right triangle; a^2 + b^2 = c^2 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " square both sides \n" ); document.write( "L^2 + W^2 = 40 \n" ); document.write( ": \n" ); document.write( "The area equation \n" ); document.write( "L*W = 12 \n" ); document.write( "L = \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "multiply equation by W^2 \n" ); document.write( "144 + W^4 = 40W^2 \n" ); document.write( ": \n" ); document.write( "A quadratic equation \n" ); document.write( "W^4 - 40W^2 + 144 = 0 \n" ); document.write( ": \n" ); document.write( "this will factor \n" ); document.write( "(W^2 - 36)(W^2 - 4) = 0 \n" ); document.write( ": \n" ); document.write( "Two solutions \n" ); document.write( "W^2 = 36 \n" ); document.write( "W = 6, call this one the length \n" ); document.write( "and \n" ); document.write( "W^2 = 4 \n" ); document.write( "W = 2, the width \n" ); document.write( ": \n" ); document.write( "P = 2(6) + 2(2) \n" ); document.write( "P = 12 + 4 \n" ); document.write( "P = 16 units is the perimeter \n" ); document.write( ": \n" ); document.write( "A = 6*2 = 12 confirm using the area \n" ); document.write( " |