document.write( "Question 273368: There are 21 animals on Farmer Cole's farm- all sheep and chickens. If the animals have a total of 56 legs, how many of each type of animal lives on his farm \n" ); document.write( "
Algebra.Com's Answer #199727 by checkley77(12844)\"\" \"About 
You can put this solution on YOUR website!
4s+2c=56
\n" ); document.write( "s+c=21 or s=21-c
\n" ); document.write( "4(21-c)+2c=56
\n" ); document.write( "84-4c+2c=56
\n" ); document.write( "-2c=56-84
\n" ); document.write( "-2c=-28
\n" ); document.write( "c=-28/-2
\n" ); document.write( "c=14 chickens.
\n" ); document.write( "s=21-14=7 sheep.
\n" ); document.write( "Proof:
\n" ); document.write( "4*7+2*14=56
\n" ); document.write( "28+28=56
\n" ); document.write( "56=56
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