document.write( "Question 273368: There are 21 animals on Farmer Cole's farm- all sheep and chickens. If the animals have a total of 56 legs, how many of each type of animal lives on his farm \n" ); document.write( "
Algebra.Com's Answer #199727 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! 4s+2c=56 \n" ); document.write( "s+c=21 or s=21-c \n" ); document.write( "4(21-c)+2c=56 \n" ); document.write( "84-4c+2c=56 \n" ); document.write( "-2c=56-84 \n" ); document.write( "-2c=-28 \n" ); document.write( "c=-28/-2 \n" ); document.write( "c=14 chickens. \n" ); document.write( "s=21-14=7 sheep. \n" ); document.write( "Proof: \n" ); document.write( "4*7+2*14=56 \n" ); document.write( "28+28=56 \n" ); document.write( "56=56 \n" ); document.write( " \n" ); document.write( " |