document.write( "Question 273337: A woman is 20 years more than the age of her daughter. In eleven years she will be 3 years less than twice her daughter's age, how old is each now?
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Algebra.Com's Answer #199704 by JBarnum(2146) $\"\"$ $\"About$

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w=woman d=daughter
\n" ); document.write( " $\"w=20%2Bd\"$
\n" ); document.write( " $\"w%2B11=2%28d%2B11%29-3\"$ use substitution for $\"w\"$
\n" ); document.write( " $\"%2820%2Bd%29%2B11=2d%2B22-3\"$ add like terms
\n" ); document.write( " $\"31%2Bd=2d%2B19\"$ subtract 19 amd d
\n" ); document.write( " $\"12=d\"$
\n" ); document.write( "use first equation
\n" ); document.write( " $\"w=20%2Bd\"$ plug in $\"d=12\"$
\n" ); document.write( " $\"w=20%2B12\"$
\n" ); document.write( " $\"w=32\"$
\n" ); document.write( "Woman is $\"highlight%2832yrs%29\"$
\n" ); document.write( "Daughter is $\"highlight%2812yrs%29\"$ \n" ); document.write( "

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