document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=4383>Question 4383</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the length of a room is 5 feet more than the width of the room. the perimeter of the room id 70 feet. find the length and width of the room. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #1997 by </B><A HREF=/tutors/aboutme.mpl?userid=arunpaul><B>arunpaul(104)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=arunpaul><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=1997\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let length of room = l<BR>\n" );
document.write( "    width of the room = w<BR>\n" );
document.write( "as per the question   l = w + 5'<BR>\n" );
document.write( "the perimeter of room = 70'<BR>\n" );
document.write( "or 2(l+w) = 70<BR>\n" );
document.write( "putting the value of l in the above equation we have<BR>\n" );
document.write( "   2(w+5+w) =70<BR>\n" );
document.write( "or 2w +5 = 70/2<BR>\n" );
document.write( "or 2w = 35 - 5<BR>\n" );
document.write( "or 2w = 30<BR>\n" );
document.write( "or  w = 30/2<BR>\n" );
document.write( "or  w = 15'<BR>\n" );
document.write( "so putting the value of w in l<BR>\n" );
document.write( "we have length of room = l = w + 5 = 15 + 5 = 20\r<BR>\n" );
document.write( "\n" );
document.write( "so length = l = 20 feet<BR>\n" );
document.write( "   width  = w = 15 feet  (Ans)<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );