document.write( "Question 273305: Need help did this problem and got it wrong:\r
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document.write( "Factor the expression.
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document.write( "x(x - y - z) + y(x - y - z)
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document.write( "put answer x to the second -2x-y to the second -yz \n" );
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Algebra.Com's Answer #199679 by Theo(13342) You can put this solution on YOUR website! x * (x - y - z) = x^2 - xy - xz (first part)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "y * (x - y - z) = yx - y^2 - yz (second part)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "since yx is the same as xy, this second part becomes:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "y * (x - y - z) = xy - y^2 - yz (second part)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "add first part and second part together and you get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(x^2 - xy - xz) + (xy - y^2 - yz) which becomes:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x^2 - xy - xz + xy - y^2 - yz.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The + xy and the - xy cancel out so the equation becomes:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x^2 - xz - y^2 - yz\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "your answer was:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x^2 - 2x - y^2 - yz\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "not sure where you got the 2x from.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "I believe that should have been zx or xz.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |