document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=273256>Question 273256</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If  measures 135, what is the length of the radius of this circle? Round your answer to two decimal places.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #199673 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=199673\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if you are talking about the circumference of the circle, then the equation is:\r<BR>\n" );
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document.write( "c = 2*pi*r\r<BR>\n" );
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document.write( "When c = 135, this formula becomes:\r<BR>\n" );
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document.write( "135 = 2*pi*r\r<BR>\n" );
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document.write( "divide both sides of this equation by 2*pi to get:\r<BR>\n" );
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document.write( "r = 135/(2*pi) which makes r = 21.48591732\r<BR>\n" );
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document.write( "rounded to the nearest 2 decimal places, that becomes 21.49.\r<BR>\n" );
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document.write( "If you are talking about the area of the circle, then the equation for that is:\r<BR>\n" );
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document.write( "a = pi*r^2\r<BR>\n" );
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document.write( "When a = 135, this formula becomes:\r<BR>\n" );
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document.write( "135 = pi*r^2\r<BR>\n" );
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document.write( "divide both sides of this equation by pi to get:\r<BR>\n" );
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document.write( "42.97183463 = r^2\r<BR>\n" );
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document.write( "take square root of both sides of this equation to get:\r<BR>\n" );
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document.write( "r = sqrt(42.97183463) = 6.555290584\r<BR>\n" );
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document.write( "rounded to the nearest 2 decimal places, that becomes r = 6.56,\r<BR>\n" );
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