document.write( "Question 273051: Professor williamson counts his midterm as 2.3 of the grade and his final as 1/3 of the grad. wendy scored only 48on the midterm. What range of scores on the final exam would put wendy's average b/w 70 and 79 inclusive? \r
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document.write( "Compare to previous exercise which is: (Professor Williams give only a midterm exam and a final exam. The semester average is computed by taking 1/3 of the midterm exam score plus 2/3 of the final exam score. To get a C Stacey must have a semester average between 70-79 inclusive. If Stacey scored only 48 on the midterm, then for what range of scores on the final exam will Stacey get a c) \n" );
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Algebra.Com's Answer #199668 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! williamson counts his midterm as 2/3 of the grade and his final as 1/3 of the grade. \n" ); document.write( "wendy scored only 48on the midterm. \n" ); document.write( "What range of scores on the final exam would put wendy's average b/w 70 and 79 inclusive? \n" ); document.write( ": \n" ); document.write( "let x = grade required for a 70 \n" ); document.write( "Count the midterm grade twice and the final once, so you have \n" ); document.write( " \n" ); document.write( "Multiply both side by 3 \n" ); document.write( "96 + x = 3(70) \n" ); document.write( "x = 210 - 96 \n" ); document.write( "x = 114, so it's hopeless, cannot make a grade of 70 \n" ); document.write( ": \n" ); document.write( "Compare to previous exercise which is: (Professor Williams give only a midterm exam and a final exam. \n" ); document.write( "The semester average is computed by taking 1/3 of the midterm exam score plus 2/3 of the final exam score. \n" ); document.write( "To get a C Stacey must have a semester average between 70-79 inclusive. \n" ); document.write( " If Stacey scored only 48 on the midterm, then for what range of scores on the final exam will Stacey get a c) \n" ); document.write( ": \n" ); document.write( "Count the midterm once and the final twice in this case \n" ); document.write( " \n" ); document.write( "Multiply both side by 3 \n" ); document.write( "48 + 2x = 3(70) \n" ); document.write( "2x = 210 - 48 \n" ); document.write( "2x = 162 \n" ); document.write( "x = \n" ); document.write( "x = 81, to get a 70 \n" ); document.write( "and \n" ); document.write( " \n" ); document.write( "Multiply both side by 3 \n" ); document.write( "48 + 2x = 3(79) \n" ); document.write( "2x = 237 - 48 \n" ); document.write( "2x = 189 \n" ); document.write( "x = \n" ); document.write( "x = 94.5, to get a 79 \n" ); document.write( ": \n" ); document.write( "Grade must be between 81 and 94.5 to have a C \n" ); document.write( " \n" ); document.write( " |