document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=33559>Question 33559</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Simplify the expression...<BR>\n" );
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document.write( "sqrt -(x^2-10x+25)\r<BR>\n" );
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document.write( "that's the square root of x^2 minus 10x plus 25. with the a negitive symbol on the outside of the square root sign. I think i need to factor this but i dont think i did it right... please help </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #19966 by </B><A HREF=/tutors/aboutme.mpl?userid=priya><B>priya(51)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=priya><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=19966\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> SO THE NEGATIVE SIGN IS ON THE OUTSIDE OF THE SQRT.\r<BR>\n" );
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document.write( "then the expression is -sqrt(x^2-10x+25)\r<BR>\n" );
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document.write( " first try to simplify the expression inside the rt.<BR>\n" );
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document.write( "          x^2-10x+25\r<BR>\n" );
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document.write( "there is a simple procedure to find the values of x and is given below<BR>\n" );
document.write( "(factorise 25 and find 2 values of x,such that the product of <BR>\n" );
document.write( "the 2 values gives u 25 and the sum of the values are -10,if u cannot do that u have to follow this formula     <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+ ALIGN=MIDDLE  ALT=\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" >)\r<BR>\n" );
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document.write( "but in this case u get values as -5  and -5,when u multiply they give u 25 and when u add them,they give u -10.\r<BR>\n" );
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document.write( "so this is written as<BR>\n" );
document.write( "           (x-5) and (x-5) ,put this value in the expression in the place of <BR>\n" );
document.write( "   x^2-10x+25.  \r<BR>\n" );
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document.write( "   therefore  we get,   - sqrt((x-5)(x-5)) \r<BR>\n" );
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document.write( "        the answer is -(x-5)       (because sqrt(a^2)=a,here sqrt((x-5)^2)=(x-5))\r<BR>\n" );
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document.write( "PRIYA </SPAN>\n" );
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