document.write( "Question 273268: Can someone please help me with this problem?
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document.write( "Multiply: 3y^2+13y+14 divided by y^2+3y+2 * 2y^2-3y-2 divided by 3y^2+22y+35\r
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document.write( "This is what I came up with. Is this correct?
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document.write( "(y+2)(3y+7)divided by (y+2)(y+1) * (y-2)(2y+1) divided by (3y+7)(y+5) equals to (y-2)(2y+1) divided by (y+1)(y+5) \n" );
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Algebra.Com's Answer #199643 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! This is what I came up with. Is this correct? \n" ); document.write( "--- \n" ); document.write( "Your factoring is correct. \n" ); document.write( "---\r \n" ); document.write( "\n" ); document.write( "[(y+2)(3y+7)]/[(y+2)(y+1)] * [(y-2)(2y+1)]/[(3y+7)(y+5)] \n" ); document.write( "--- \n" ); document.write( "Cancel the y+2 factor: \n" ); document.write( "Cancel the 3y+7 factor: \n" ); document.write( "--- \n" ); document.write( "(1/(y+1) \n" ); document.write( "--- \n" ); document.write( "equals to (y-2)(2y+1) divided by (y+1)(y+5) \n" ); document.write( "--- \n" ); document.write( "You are correct. \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |