document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=273178>Question 273178</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two kinds of candy sell for 30 pesos and 40  pesos per kilo. How many kilos of each should be used to make 20 kilos of a mixture to sell for 35 pesos per kilo? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #199609 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=199609\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 40x+30(20-x)=35*20<BR>\n" );
document.write( "40x+600-30x=700<BR>\n" );
document.write( "10x=700-600<BR>\n" );
document.write( "10x=100<BR>\n" );
document.write( "x=100/10<BR>\n" );
document.write( "x=10 kilos of 40 pesos is needed.<BR>\n" );
document.write( "20-10=10 kilos of 30 pesos is needed.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( "40*10+30*10=35*20<BR>\n" );
document.write( "400+300=700<BR>\n" );
document.write( "700=700 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );