document.write( "Question 273095: a Woman has 11 coins, consisting of nickels and dimes. she has three more dimes than nickels. how many of each type of coin does she have if the total value of the coins is 90 cents?
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Algebra.Com's Answer #199590 by josmiceli(19441) $\"\"$ $\"About$

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Let $\"n\"$ = number of nickels
\n" ); document.write( "Let $\"d\"$ = number of dimes
\n" ); document.write( "given:
\n" ); document.write( " $\"n+%2B+d+=+11\"$
\n" ); document.write( " $\"d+=+n+%2B+3\"$
\n" ); document.write( " $\"5n+%2B+10d+=+90\"$
\n" ); document.write( "By substitution:
\n" ); document.write( " $\"5n+%2B+10%2A%28n+%2B+3%29+=+90\"$
\n" ); document.write( " $\"5n+%2B+10n+%2B+30+=+90\"$
\n" ); document.write( " $\"15n+=+90+-+30\"$
\n" ); document.write( " $\"15n+=+60\"$
\n" ); document.write( " $\"n+=+4\"$
\n" ); document.write( "and
\n" ); document.write( " $\"n+%2B+d+=+11\"$
\n" ); document.write( " $\"4+%2B+d+=+11\"$
\n" ); document.write( " $\"d+=+7\"$
\n" ); document.write( "She has 7 dimes and 4 nickels
\n" ); document.write( "check:
\n" ); document.write( " $\"5n+%2B+10d+=+90\"$
\n" ); document.write( " $\"5%2A4+%2B+10%2A7+=+90\"$
\n" ); document.write( " $\"20+%2B+70+=+90\"$
\n" ); document.write( " $\"90+=+90\"$
\n" ); document.write( "OK \n" ); document.write( "

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