document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=273009>Question 273009</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve the following systems of equations.<BR>\n" );
document.write( "x+2y=3<BR>\n" );
document.write( "2x-y=1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #199513 by </B><A HREF=/tutors/aboutme.mpl?userid=persian52><B>persian52(161)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=persian52><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=persian52><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=199513\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I solved it by using the substitution method, if am right other wise explain in more detail what you looking for. HOPE i helped! &#9786;<BR>\n" );
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document.write( "x+2y=3_2x-y=1\r<BR>\n" );
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document.write( "Since 2y does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting 2y from both sides.<BR>\n" );
document.write( "x=-2y+3_2x-y=1\r<BR>\n" );
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document.write( "Replace all occurrences of x with the solution found by solving the last equation for x.  In this case, the value substituted is -2y+3.<BR>\n" );
document.write( "x=-2y+3_2(-2y+3)-y=1\r<BR>\n" );
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document.write( "Multiply 2 by each term inside the parentheses.<BR>\n" );
document.write( "x=-2y+3_(-4y+6)-y=1\r<BR>\n" );
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document.write( "Since -4y and -y are like terms, subtract y from -4y to get -5y.<BR>\n" );
document.write( "x=-2y+3_-5y+6=1\r<BR>\n" );
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document.write( "Since 6 does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting 6 from both sides.<BR>\n" );
document.write( "x=-2y+3_-5y=-6+1\r<BR>\n" );
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document.write( "Add 1 to -6 to get -5.<BR>\n" );
document.write( "x=-2y+3_-5y=-5\r<BR>\n" );
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document.write( "Divide each term in the equation by -5.<BR>\n" );
document.write( "x=-2y+3_-(5y)/(-5)=-(5)/(-5)\r<BR>\n" );
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document.write( "Simplify the left-hand side of the equation by canceling the common terms.<BR>\n" );
document.write( "x=-2y+3_y=-(5)/(-5)\r<BR>\n" );
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document.write( "Simplify the right-hand side of the equation by simplifying each term.<BR>\n" );
document.write( "x=-2y+3_y=1\r<BR>\n" );
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document.write( "Replace all occurrences of y with the solution found by solving the last equation for y.  In this case, the value substituted is 1.<BR>\n" );
document.write( "x=-2(1)+3_y=1\r<BR>\n" );
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document.write( "Multiply -2 by each term inside the parentheses.<BR>\n" );
document.write( "x=-2+3_y=1\r<BR>\n" );
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document.write( "Add 3 to -2 to get 1.<BR>\n" );
document.write( "x=1_y=1\r<BR>\n" );
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document.write( "This is the solution to the system of equations.<BR>\n" );
document.write( "1st Answer: x=1<BR>\n" );
document.write( "2nd Answer: y=1 </SPAN>\n" );
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