document.write( "Question 33543: A train traveling at 40 miles per hour leaves for a certain town. One hour later, a bus traveling at 50 miles per hours leaves for the same town and arrives at the same time as the train. If both the train and the bus traveled in a straight line, how far is the town from where they started?\r
\n" ); document.write( "\n" ); document.write( "Please help me I think the answer is 200 but I don't know how to set the problem up
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Algebra.Com's Answer #19951 by Cintchr(481)\"\" \"About 
You can put this solution on YOUR website!
\"+rt=d+\"
\n" ); document.write( "In this case, the distance for both is the same, so for our convenience the train's variables are in caps.
\n" ); document.write( "\"+RT+=+rt+\"
\n" ); document.write( "r=50
\n" ); document.write( "t= T-1 (it started an hour later)
\n" ); document.write( "R=40
\n" ); document.write( "T= this is what we will solve for
\n" ); document.write( "\"+%2840%29T+=+%2850%29%28T-1%29+\"
\n" ); document.write( "Solve for T
\n" ); document.write( "\"+40T+=+50T-50+\"
\n" ); document.write( "Subtract 50T
\n" ); document.write( "\"+-10T=-50+\"
\n" ); document.write( "divide by -10
\n" ); document.write( "\"+T=5+\"
\n" ); document.write( "So if the Train takes 5 hours, the bus takes 4.\r
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\n" ); document.write( "\n" ); document.write( "CHECK
\n" ); document.write( "\"+RT+=+rt+\"
\n" ); document.write( "\"+40%285%29+=+50%284%29+\"
\n" ); document.write( "\"+200+=+200+\"
\n" ); document.write( "and this IS the distance.\r
\n" ); document.write( "\n" ); document.write( "This is a duplicate of problem 33542
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