document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=272888>Question 272888</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How much 35% copper alloy should be melted with 37 kg of 75% copper alloy to produce an alloy which is 50% copper.  If necessary round your answer to the nearest tenth. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #199481 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=199481\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .75*37+.35X=.50(37+X)<BR>\n" );
document.write( "27.75+.35X=18.5+.50X<BR>\n" );
document.write( ".35X-.50X=18.5-27.75<BR>\n" );
document.write( "-.15X=-9.25<BR>\n" );
document.write( "X=-9.25/-.15<BR>\n" );
document.write( "X=61.7 KG OF 35% COPPER IS USED.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( ".75*37+.35*61.7=.50(37+61.7)<BR>\n" );
document.write( "27.8+21.6=.50*98.7<BR>\n" );
document.write( "49.4=49.49.4 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );